PHP Conference China 2020

$argv

(PHP 4, PHP 5, PHP 7)

$argvArray of arguments passed to script

Description

Contains an array of all the arguments passed to the script when running from the command line.

Note: The first argument $argv[0] is always the name that was used to run the script.

Note: This variable is not available when register_argc_argv is disabled.

Examples

Example #1 $argv example

<?php
var_dump
($argv);
?>

When executing the example with: php script.php arg1 arg2 arg3

The above example will output something similar to:

array(4) {
  [0]=>
  string(10) "script.php"
  [1]=>
  string(4) "arg1"
  [2]=>
  string(4) "arg2"
  [3]=>
  string(4) "arg3"
}

Notes

Note:

This is also available as $_SERVER['argv'].

See Also

  • getopt() - Gets options from the command line argument list
  • $argc

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User Contributed Notes 4 notes

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87
tufan dot oezduman at googlemail dot com
9 years ago
Please note that, $argv and $argc need to be declared global, while trying to access within a class method.

<?php
class A
{
    public static function
b()
    {
       
var_dump($argv);
       
var_dump(isset($argv));
    }
}

A::b();
?>

will output NULL bool(false)  with a notice of "Undefined variable ..."

whereas global $argv fixes that.
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29
hamboy75 at example dot com
6 years ago
To use $_GET so you dont need to support both if it could be used from command line and from web browser.

foreach ($argv as $arg) {
    $e=explode("=",$arg);
    if(count($e)==2)
        $_GET[$e[0]]=$e[1];
    else   
        $_GET[$e[0]]=0;
}
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4
php at simoneast dot net
4 years ago
Sometimes $argv can be null, such as when "register-argc-argv" is set to false.  In some cases I've found the variable is populated correctly when running "php-cli" instead of just "php" from the command line (or cron).
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0
Steve Schmitt
11 years ago
If you come from a shell scripting background, you might expect to find this topic under the heading "positional parameters".
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