ArrayObject::getArrayCopy

    (PHP 5, PHP 7, PHP 8)

    ArrayObject::getArrayCopy — Cria uma cópia do ArrayObject

    Descrição

    public ArrayObject::getArrayCopy(): array

    Exporta o ArrayObject para um array.

    Parâmetros

    Esta função não possui parâmetros.

    Valor Retornado

    Retorna uma cópia do array. Quando o ArrayObject se refere a um objeto, um array com as propriedades desse objeto será retornado.

    Exemplos

    Exemplo #1 Exemplo de ArrayObject::getArrayCopy()

    <?php
    // Array de frutas disponíveis
    $fruits = array("lemons" => 1, "oranges" => 4, "bananas" => 5, "apples" => 10);

    $fruitsArrayObject = new ArrayObject($fruits);
    $fruitsArrayObject['pears'] = 4;

    // cria uma cópia do array
    $copy = $fruitsArrayObject->getArrayCopy();
    var_dump($copy);

    ?>

    O exemplo acima produzirá:

    array(5) {
  ["lemons"]=>
  int(1)
  ["oranges"]=>
  int(4)
  ["bananas"]=>
  int(5)
  ["apples"]=>
  int(10)
  ["pears"]=>
  int(4)
}

    Melhore Esta Página

    Aprenda Como Melhorar Esta Página • Envie uma Solicitação de Modificação • Reporte um Problema
    ＋adicionar nota

    Notas de Usuários 5 notes

    up
    4
    Ivo von Putzer
    13 years ago
    If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
    <?php
    public function __construct( $array = array(), $flags = 2 )
    {
    // let’s give the objects the right and not the inherited name
    $class = get_class($this);

    foreach(    $array as $offset => $value)
    $this->offsetSet($offset, is_array($value) ? new $class($value) : $value);

    $this->setFlags($flags);
    }
    ?>

    That’s the way I solved it:

    <?php
    public function getArray($recursion = false)
    {
    // just in case the object might be multidimensional
    if ( $this === true)
    return     $this->getArrayCopy();

    return     array_map( function($item){
    return     is_object($item) ? $item->getArray(true) : $item;
    },     $this->getArrayCopy() );
    }
    ?>

    Hope this was useful!
    up
    2
    spidgorny at gmail dot com
    8 years ago
    <?php
    $data     = $likeArray->getArrayCopy();
    ?>
    will NOT be magically called if you cast to array. Although I've expected it.
    <?php
    $nothing     = (array)$likeArray;
    ?>
    Here, $data != $nothing.
    up
    1
    php at webflips dot net
    11 years ago
    "When the ArrayObject refers to an object an array of the public properties of that object will be returned."

    This description does not seem to be right:

    <?php
    class A
    {
    public     $var = 'var';
    protected     $foo = 'foo';
    private     $bar = 'bar';
    }

    $o = new ArrayObject(new A());
    var_dump($o->getArrayCopy());

    /*
    Dumps:

    array(3) {
    ["var"]=>
    string(3) "var"
    ["*foo"]=>
    string(3) "foo"
    ["Abar"]=>
    string(3) "bar"
    }
    */
    ?>

    So it does not only include the public properties.
    up
    1
    jlshor at buffalo dot edu
    8 years ago
    Is there a difference between casting to an array and using this function?

    For instance, if we have:
    $arrayObject = new ArrayObject([1, 2, 3]);

    Is there a difference between these:
    $array = (array) $arrayObject;
    vs
    $array = $arrayObject->getArrayCopy();

    If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
    up
    0
    sorcerer
    8 years ago
    When I used print_r ($fruitsArrayObject) instead of print_r ($copy), i.e. ignoring the getArrayCopy() step, I still got the same output. Why?
    ＋adicionar nota
    To Top