betterCode() PHP 2025

    get_included_files

    (PHP 4, PHP 5, PHP 7, PHP 8)

    get_included_files — Возвращает массив имён включённых в скрипт файлов

    Описание

    get_included_files(): array

    Получает имена всех файлов, которые были включены в скрипт с использованием include, include_once, require или require_once.

    Список параметров

    Сигнатура функции не содержит параметров.

    Возвращаемые значения

    Возвращает массив, содержащий имена всех файлов.

    Скрипт, который был загружен изначально, рассматривается как "включённый файл", поэтому он также попадёт в список файлов включённых функцией include или другими.

    Файлы, добавляемые в скрипт неоднократно, попадут в массив только в одном экземпляре.

    Примеры

    Пример #1 Пример использования get_included_files()

    <?php
    // Этот скрипт расположен в файле abc.php

    include 'test1.php';
    include_once     'test2.php';
    require     'test3.php';
    require_once     'test4.php';

    $included_files = get_included_files();

    foreach (    $included_files as $filename) {
    echo     "$filename\n";
    }

    ?>

    Результат выполнения приведённого примера: 

    /path/to/abc.php
/path/to/test1.php
/path/to/test2.php
/path/to/test3.php
/path/to/test4.php

    Смотрите также

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    Инструкция • Исправление • Сообщение об ошибке
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    Примечания пользователей 7 notes

    up
    23
    keystorm :at: gmail dotcom
    21 years ago
    As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
    If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:

    index.php
    a.php
    b.php

    while in PHP<5 the array would be:

    a.php
    b.php

    If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.

    If you also want to ensure current script is being included and not run independently you should evaluate following expression:

    __FILE__ != $_SERVER['SCRIPT_FILENAME']

    If this expression returns TRUE, current script is being included or required.
    up
    14
    yarco dot w at gmail dot com
    18 years ago
    If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:

    main.php:
    <?php
    function blockit()
    {
    $buf = get_included_files();
    return     $buf[0] != __FILE__;
    }

    blockit() and exit("You can not include a MAIN file as a part of your script.");

    print     "OK";
    ?>

    So other script couldn't include main.php to modify its internal global vars.
    up
    6
    D
    5 years ago
    It's perhaps not clear from the existing docs that the returned list contains nested include files as well.

    That is, if A.php includes B.php, and B.php includes C.php, the result returned when calling get_included_files() from inside A.php WILL contain 'C.php'.
    up
    5
    donikuntoro at integraasp dot com
    14 years ago
    This function aims to perform filtering of files that have been included :

    <?php
    function setIncludeFiles($arrayInc = array()){
    $incFiles = get_included_files();
    if((    count($arrayInc)>0)&&(count($incFiles)>0)){
    $aInt = array_intersect($arrayInc,$incFiles);
    if(    count($aInt)>0){
    return     false;
    }elseif(    count($aInt)<1) {
    foreach(    $arrayInc as $inc){
    if(    is_file($inc))
    include(    $inc);
    else{
    return     false;
    }
    }
    }
    }else{
    return     false;
    }
    }
    ?>

    Usage :

    <?php
    $toBeInclude     = array('/data/your_include_files_1.php',
    '/data/your_include_files_2.php',
    '/data/your_include_files_3.php',
    );
    setIncludeFiles($toBeInclude);
    ?>

    Return false if something goes wrong.
    up
    3
    RPaseur at NationalPres dot org
    19 years ago
    As is often the case, YMMV. I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:

    SCRIPT_FILENAME: /var/www/cgi-bin/php441
    __FILE__: /raid/home/natpresch/natpresch/RAY_included.php

    As an alternative:

    count(get_included_files());

    Gives one when the script is standalone and always more than one when the script is included.
    up
    0
    miqrogroove at gmail dot com
    1 month ago
    Correction to the top comment:

    The modern behavior of this function was not introduced in PHP 5. The change can be seen when testing versions less than 4.3.0.

    So, backwards compatibility with v4.2.3 and earlier requires a version check.
    up
    0
    Aurelien Marchand
    3 years ago
    This is a great way to emulate Python's '__name__ = "__main__"'

    <?php
    if(get_included_files()[0] === __FILE__) doStuff();
    ?>
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